SRAM AXS/QUARQ/chainring compatibility
Hi,
I have Force AXS. (12 speed with flattop chain). I would like to see if there are alternatives to using Force or Red powermeters, because A: I dont like the plasticy look of Force, and B: I would like to be able to change chain rings separately. (Red wont allow that) Since i have dub bottom bracket and 8 bolt spider interface (obviously) my question is, will this work: https://www.sram.com/en/quarq/models/pm-dz-spdr-d1 Either with my existing Force crankarms, or with these crankarms: https://www.sram.com/en/quarq/models/fc-qrq-assy-d1 .. And if so: what chain line would i get? With the compatible chain rings for Flattop chains (such as these: X-CarboRing 48 x 110 X-AXS - X-CarboRing - Chainrings - Products) would i be able to achieve the correct 45mm chainline? (this is apparently important for the FD to shift properly) I hope the question(s) make sense, and I hope they haven't been answered elsewhere (i did search). Thank you in advance! |
Originally Posted by flx100
(Post 21548267)
Hi,
I have Force AXS. (12 speed with flattop chain). I would like to see if there are alternatives to using Force or Red powermeters, because A: I dont like the plasticy look of Force, and B: I would like to be able to change chain rings separately. (Red wont allow that) Since i have dub bottom bracket and 8 bolt spider interface (obviously) my question is, will this work: https://www.sram.com/en/quarq/models/pm-dz-spdr-d1 Either with my existing Force crankarms, or with these crankarms: https://www.sram.com/en/quarq/models/fc-qrq-assy-d1 .. And if so: what chain line would i get? With the compatible chain rings for Flattop chains (such as these: X-CarboRing 48 x 110 X-AXS - X-CarboRing - Chainrings - Products) would i be able to achieve the correct 45mm chainline? (this is apparently important for the FD to shift properly) I hope the question(s) make sense, and I hope they haven't been answered elsewhere (i did search). Thank you in advance! |
Thanks for the reply! Do you happen to know the reason why I cant use my current arm? The interface is the same. Does it have to do with the way the powermeter measures?
Yes, i have considered pedals - but i just got some other pedals, and i am in any event looking to replace the force chain rings, which i dont like the look of. (I know, silly me) Is there really no crank/power meter that works with AXS that is NOT Force or Red? There are multiple brands producing chainrings for Flattop chains - how do they achieve the correct chain line? |
Originally Posted by flx100
(Post 21549134)
Thanks for the reply! Do you happen to know the reason why I cant use my current arm? The interface is the same. Does it have to do with the way the powermeter measures?
Yes, i have considered pedals - but i just got some other pedals, and i am in any event looking to replace the force chain rings, which i dont like the look of. (I know, silly me) Is there really no crank/power meter that works with AXS that is NOT Force or Red? There are multiple brands producing chainrings for Flattop chains - how do they achieve the correct chain line? TLDR: buying the spider alone and installing that should work just fine with your current AXS 8-bolt cranks. |
Wow, thank you for all the great info!
Yea, in the meantime i got some info from SRAM - obviously they can't recommend a 'hack' like this, but the person did confirm the chainline should be the same with this spider. They avoided the question if i could use my existing Force crank arms, or if i had to buy the Quarq arms. But i can try first. What this means (hopefully) is that there's an alternative to the Red AXS powermeter with more flexibility in chainrings, and you don't have to throw away the powermeter when the chainrings need replacing. Great! |
UPDATE
The Force AXS crank arms ARE compatible with the Quarq DZERO dub power meter. I installed them and it worked fine with the Carbon-TI AXS specific chainrings. Chainline is perfect and all is good. Later i actually got the 'matching' Quarq crank arms only for the weight savings, which are substantial. (just wanted to follow up in case anybody had a similar question) |
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